c/c++值传递,引用传递问题

例子:

#include <iostream>

using namespace std;

void test1( int *a1 )

{  
	cout<< "&a1 = " << a1 << endl;
	a1 = new int( 5 );
	cout<< "&a11 = " << a1 << endl;
   cout<< "*a1 = " << *a1 << endl;

}

void test2(int * & a2)

{  
	cout<< "&a2 = " << a2 << endl;
	cout<< "*a21 = " << *a2 << endl;
	a2 = new int( 5 );
	cout<< "&a2 = " << a2 << endl;
   cout<< "*a2 = " << *a2 << endl;

}

int main()

{  
	int *p =new int( 1 );
	cout<< "&p = " << p << endl;
   test1( p);
   cout<< "test1: *p1 = " << *p << endl;
   	test2( p);
	cout<< "test2 &p2 = " << p << endl;
   cout<< "test2: *p2 = " << *p << endl;

}

打印结果如下:
&p = 0x17d9c20
&a1 = 0x17d9c20
&a11 = 0x17dac50
*a1 = 5
test1: *p1 = 1
&a2 = 0x17d9c20
*a21 = 1
&a2 = 0x17dac70
*a2 = 5
test2 &p2 = 0x17dac70
test2: *p2 = 5

结论:
1.在c/c++函数传递值属于值传递,不是引用传递,需要引用传递需要f(int &a)方式,这样就是引用传递。
2.f(Object a)也是值传递,会调用Object的拷贝构造函数,需要引用传递使用f(Object &a).
3.java中8中基本数据类型函数传递属于值传递,对象传递属于引用传递,例如f(int a)是值传递,f(Object a )是引用传递。

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转载自blog.csdn.net/pangrui201/article/details/97782351