jquery动态生成form表单并提交

<button onclick="toDetailPage(this, '1234', 'test')">测试</button>
<script type="text/javascript" language="javascript">
function toDetailPage(object, uid, namespace) {
    var form = $("<form method='post'></form>");
    form.attr({"action":"data/index.do"});
    var input1 = $("<input type='hidden'>").attr("name", "namespace").val(namespace);
    var input2 = $("<input type='hidden'>").attr("name", "labels").val($(object).attr("data-labels"));
    var input3 = $("<input type='hidden'>").attr("name", "uid").val(uid);
    form.append(input1);
    form.append(input2);
    form.append(input3);
    // 这步很重要，如果没有这步，则会报错无法建立连接
    $("body").append($(form));
    form.submit();
}
</script>