1042 Shuffling Machine (20分)/简单模拟/观察规律

题目链接
刚开始没有想太多，直接把每个牌面值都作为了string对象。由于VS2017有替换功能，输了S1~S13之后，替换即可，不需要全部手敲。这样的好处是不需要多想，但是代码有些冗杂。

#include<iostream>
#include<string>
using namespace std;
int main() {
	string s[55] = {" ", "S1","S2","S3","S4","S5","S6","S7","S8","S9","S10","S11","S12","S13",
		"H1","H2","H3","H4","H5","H6","H7","H8","H9","H10","H11","H12","H13",
		"C1","C2","C3","C4","C5","C6","C7","C8","C9","C10","C11","C12","C13",
		"D1","D2","D3","D4","D5","D6","D7","D8","D9","D10","D11","D12","D13" ,
		"J1","J2" };
	string an[55];
	int order[55],k;
	cin >> k;
	for (int i = 1; i <= 54; i++) {
		cin >> order[i];
	}
	while (k--) {
		for (int i = 1; i <= 54; i++) {
			an[order[i]] = s[i];
		}
		for (int i = 1; i <= 54; i++) {
			s[i] = an[i];  //保存每次操作的结果
		}
	}
	cout << an[1];
	for (int i = 2; i <= 54; i++) {
		cout << " " << an[i];
	}
	return 0;
}

观察可以发现，最开始的牌面顺序是很有规律的，因此可以根据顺序确定牌面值。

#include<iostream>
using namespace std;
int main() {
	char ma[] = "SHCDJ"; //映射表
	int an[55],t[55],order[55], k;
	cin >> k;
	for (int i = 1; i <= 54; i++) {
		cin >> order[i];
		t[i] = i;  //初始化
	}
	while (k--) {
		for (int i = 1; i <= 54; i++) {
			an[order[i]] = t[i];
		}
		for (int i = 1; i <= 54; i++) {
			t[i] = an[i]; //保存每次操作的结果
		}
	}
	for (int i = 1; i <= 54; i++) {
		if (i != 1) cout << " ";
		an[i] = an[i] - 1;
		cout << ma[an[i]/13]<<an[i]%13+1;
	}
	return 0;
}