1057 数零壹 (20分)

1057 数零壹 (20分)

原题链接：传送门

一、题目：

二、解析：

AC代码：

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Scanner;

/**
 * 1057 数零壹 (20分)
 * 
 * @author: ChangSheng 
 * @date:   2020年1月3日 下午6:52:56
 */
public class Main {
	public static void main(String[] args) throws IOException {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		Scanner s = new Scanner(System.in);
		String line = in.readLine();
		int sum = -1; 
		for (int i = 0; i < line.length(); i++) {
			char c = line.charAt(i);
			if (c >= 'a' && c <= 'z') {
				sum += (int) c - 96;
			} else if (c >= 'A' && c <= 'Z') {
				sum += (int) c - 64;
			}
		}
		if (sum == -1) {
			System.out.println(0+" "+0); // 确保有字母
			return;
		} else {
			sum++;
		}
		// 转换成二进制数0
		String b = Integer.toBinaryString(sum);
		int count0 = 0, count1 = 0;
		for (int i = 0; i < b.length(); i++) {
			if (b.charAt(i) == '0') {
				count0++;
			} else if (b.charAt(i) == '1') {
				count1++;
			}
		}
		System.out.println(count0+" "+count1);
	}
}