java实现浮点数转换成人民币读法字符串

 
package crazyit;

public class Num2Rmb {

    private String[] hanArr = {"零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖"};
    private String[] danArr = {"十", "百", "千", "万"};
//    //此方法【数组】仅作参考
//    private String[] div(double num){
//    	
//        long zheng = (long)num;
//        long part = Math.round((num-zheng)*100);
//        return new String[]{zheng + " ", String.valueOf(part)};
//        
//    }

    //读取传进的参数
    private String maString(double mnumString) {
    //将mnumString 强制类型转化为long，取整数部分
    	long mnumint = (long)mnumString;
    	long part = Math.round((mnumString - mnumint) * 100);
    	String result = "";
    	String result1 = "";
    	String test = "";
    	long temp2 ;    	
    	int count = 0;
    	
    	//调用小数方法
    	result1 = partString(part);
    	
    	
    	// 主要思想：利用循环导出后四位
    	do {	
    		count++;
    		temp2 = mnumint % 10000;
    		
    		test = String.valueOf(temp2);
    		if (mnumint == 0) {
				continue;
			}
    		
    		switch (count) {
			case 1:
					result = fourString(test) + result;
				break;
			case 2:
				//对万到千万是否全部为0情况的判断
				 if (fourString(test)=="") {
					 result = fourString(test) + result;
					
				}
				 else {
					result = fourString(test) +"万" + result;
				}
				break;
			case 3:
				
				result = fourString(test) +"亿" + result;
			default:
				break;
			}
    		mnumint = mnumint / 10000;
    	} while (mnumint != 0);
    	
    	
    	if (part == 0) {
			return result + "圆整";
		} else {
			return result + "圆" + result1;
		}
    	
	}
    
    //封装一个每四位一读的方法
    private String fourString(String numStr){
    	
    	String result = "";
    	int numLen = numStr.length();
    	
    	for(int i = 0; i < numLen ; i++)
    	{
    		int num = numStr.charAt(i) - 48;
				if (i !=numLen -1 && num != 0) 
        		{
        			
    				result += hanArr[num] + danArr[numLen - 2 -i];
    				
    			}
	    		else 
	    		{
	    			if (num == 0)
	    			{
	    				//如果是在首位或末位为0则不读
	    				if (i == numLen-1 || i == 0)
	    					continue;
	    				else if ((numStr.charAt(i+1) - 48) == 0){//如果连续两位是0不读
							continue;
						} 	
	    			}
						result += hanArr[num];
				}
			
    	}
    	return result;
    }
    
    //封装一个小数的读法
    private String partString(long num) {
		String result = "";
		int test;
		test = (int) (num / 10);
		result = hanArr[test] + "角";
		result += hanArr[(int)(num % 10)] + "分";
		return result;
	}
	public static void main(String[] args) {
		// TODO Auto-generated method stub  
		Num2Rmb nRmb = new Num2Rmb();
//		System.out.println(Arrays.toString(nRmb.div(2342.342)));
		System.out.println(nRmb.maString(100000001));
	}

}
java实现浮点数转换成人民币读法字符串,希望大家多多指教！

java实现浮点数转换成人民币读法字符串

猜你喜欢
