实现m的n次幂

 m的n次幂
 1:       3
 2:       9
 3:      27
 4:      81
 5:     243

#include <stdio.h>

int power(int x, int n)
{
    if (n==0)
		return 1;
    if (n%2)
		return power(x*x, (n-1)/2) * x;
    else     
		return power(x*x,     n/2);
}

int main()
{
    int i;
    for (i=1; i<=10; i++)
        printf("%2d:%8d\n", i, power(2, i));
    return 0;
}