Given a binary tree, flatten it to a linked list in-place.
For example, given the following tree:
1
/ \
2 5
/ \ \
3 4 6
The flattened tree should look like:
1
\
2
\
3
\
4
\
5
\
6
考察:将二叉树转换为右子树;
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void flatten(TreeNode* root) {
if (root == NULL)
return ;
if (root->left)
flatten(root->left);
if (root->right)
flatten(root->right);
TreeNode *cur = root->right;
root->right = root->left;
root->left = NULL;
while(root->right)
root = root->right;
root->right = cur;
}
}