python--正则匹配首尾标签中间的内容

import re

it = re.finditer(r"<url>.*?</url>", '被筛选字符串')   # 匹配url标签里的内容
# it = re.finditer(r"<command>.*?</command>", con)   # 匹配标签里的内容,有换行符\n导致匹配失败
it2 = re.finditer(r"<command>[\s\S]*?</command>", '被筛选字符串')   # 成功匹配方法1
# it = re.finditer(r"<command>[\d\D]*?</command>", con)  # 成功匹配方法2

for match in it:
   ret = match.group()
   print(ret)
for match in it2:
   ret = match.group()
   print(ret)

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转载自www.cnblogs.com/lutt/p/12207855.html