1 用字典的方法去重

方法1，用字典去重
dict1(I) = ""
方法2，用字典去重 + 统计次数
dict2(I) = dict2(I) + 1
方法3，用字典报重复，但没去重复
If Not dict3.exists(I) Then

Sub test_dict1()
Dim dict1 As Object
Set dict1 = CreateObject("scripting.dictionary")

Dim dict2 As Object
Set dict2 = CreateObject("scripting.dictionary")

Dim dict3 As Object
Set dict3 = CreateObject("scripting.dictionary")


arr1 = Range("b1:b10")

'去重
For Each I In arr1
   dict1(I) = ""
Next

For Each J In dict1.keys()
   Debug.Print J
Next
Debug.Print


'去重 + 统计次数
For Each I In arr1
   dict2(I) = dict2(I) + 1
Next

For Each J In dict2.keys()
   Debug.Print J
Next
Debug.Print

For Each K In dict2.items()
   Debug.Print K
Next
Debug.Print



For Each I In arr1
    If Not dict3.exists(I) Then
       dict3.Add I, ""
    Else
       Debug.Print "存在重复值"
       Exit Sub
    End If
Next
End Sub

2 用数组的方法去重

2.1 用数组循环的方法，去数组重复也可以

双循环
关键点1：双循环的目的是，循环拿1个数组，和另外一个循环的所有数做对比
关键点2：在外层赋值
关键点3：赋值的计数变量得独立，因为不知道有几个非重复数

Sub test_arr1()
Dim arr2

arr1 = Array(1, 2, 3, 4, 5, 1, 2, 3, 1, 2, 1)
ReDim arr2(UBound(arr1))    '在外面需要1次redim到位

For i = LBound(arr1) To UBound(arr1)
   For j = LBound(arr2) To UBound(arr2)

      If arr1(i) = arr2(j) Then
         GoTo line1
      End If
   Next
   arr2(k) = arr1(i)
   k = k + 1
line1: Next

For Each i In arr2
   Debug.Print i
Next

End Sub

2.2 用循环数组方法，判断每次内部循环，每次是否可以走一个完整循环

判断每次内部循环，每次是否可以走一个完整循环
为了配合后面得index选择性的停在ubound+1上，否则都停在ubound+1上没法区分
array的index指针停在ubound+1就证明内部循环完整走完没有exit for,证明无重复

Sub test_arr2()
Dim arr2

arr1 = Array(1, 2, 3, 4, 5, 1, 2, 3, 1)
ReDim arr2(LBound(arr1) To UBound(arr1))  '这样也没问题，一般有重复的列肯定更长
'ReDim arr2(LBound(arr1) To 99999)  这样也可以，就是故意搞1个极大数

K = 0
For I = LBound(arr1) To UBound(arr1)
    For J = LBound(arr2) To K
        If arr1(I) = arr2(J) Then
           Exit For         '为了配合后面得index选择性的停在ubound+1上，否则都停在ubound+1上没法区分
        End If
    Next
    If J = K + 1 Then       'array的index指针停在ubound+1就证明内部循环完整走完没有exit for,证明无重复
       arr2(K) = arr1(I)
       K = K + 1
    End If
Next

Debug.Print
For Each m In arr2
   Debug.Print m;
Next
Debug.Print

End Sub

2.3用数组的方法查重复次数

2.3.1 用数组的方法查某个目标值的重复次数

Sub test001()
'查某个值得重复次数

arr1 = Array(1, 2, 3, 4, 5, 1, 2, 3, 6, 7, 8, 9)
target1 = 1

Debug.Print "arr1的最小index=" & LBound(arr1)
Debug.Print "arr1的最大index=" & UBound(arr1)

For I = LBound(arr1) To UBound(arr1)
    If arr1(I) = target1 Then
       Debug.Print target1 & "第" & m & "个" & "index=" & I
    End If
Next


End Sub

2.3.2 用数组+字典的方法查每个元素重复次数

查所有元素的次数


Sub test002()
'如果用循环方法查每个重复的值的重复次数
 
arr1 = Array(1, 2, 3, 4, 5, 1, 2, 3, 6, 7, 8, 9)
Dim dict1 As Object
Set dict1 = CreateObject("scripting.dictionary")

Debug.Print "arr1的最小index=" & LBound(arr1)
Debug.Print "arr1的最大index=" & UBound(arr1)
arr2 = arr1


For I = LBound(arr1) To UBound(arr1)
    m = 1
    For J = LBound(arr2) To UBound(arr2)
        If arr1(I) = arr2(J) Then
           dict1(arr1(I)) = m
           m = m + 1
        End If
    Next
Next


For Each I In dict1.keys()
    Debug.Print I & "," & dict1(I)
Next



End Sub

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只查部分元素的重复次数

Sub test002()
'如果用循环方法查每个重复的值的重复次数
 
arr1 = Array(1, 2, 3, 4, 5, 1, 2, 3, 6, 7, 8, 9)
Dim dict1 As Object
Set dict1 = CreateObject("scripting.dictionary")

Debug.Print "arr1的最小index=" & LBound(arr1)
Debug.Print "arr1的最大index=" & UBound(arr1)
arr2 = arr1


For I = LBound(arr1) To UBound(arr1)
    m = 1
    For J = LBound(arr2) To UBound(arr2)
        If arr1(I) = arr2(J) Then
              If m >= 2 Then
                 dict1(arr1(I)) = m
              End If
           m = m + 1
        End If
    Next
Next


For Each I In dict1.keys()
    Debug.Print I & "," & dict1(I)
Next



End Sub

2.3.3 用纯数组的方法查呢？

不够好
因为还是得先去重，否则就会如下很愚蠢的显示结果


Sub test002()
'如果用循环方法查每个重复的值的重复次数
 
arr1 = Array(1, 2, 3, 4, 5, 1, 2, 3, 6, 7, 8, 9)

Debug.Print "arr1的最小index=" & LBound(arr1)
Debug.Print "arr1的最大index=" & UBound(arr1)
arr2 = arr1   '每个元素必然至少重复1次


For I = LBound(arr1) To UBound(arr1)
    m = 0
    For J = LBound(arr2) To UBound(arr2)
        If arr1(I) = arr2(J) Then
           m = m + 1
        End If
    Next
    Debug.Print arr1(I) & "重复了" & m & "次"
Next


End Sub