双向链表的删除与插入

 1.双向链表(第一个节点的前驱结点为空,最后一个节点的后继节点为空)

class Node {
    int val;
    Node next;//后继引用
    Node prev;//前驱引用
    Node(int val) {
        this.val = val;
    }
}
public class MyLinkedList {
    private Node head = null;
    private Node last = null;
    private int size=0;
    public void pushFront(int val){
        Node node=new Node(val);
        node.next=head;
        if(head!=null) {
            head=node;
            head.prev = node;
        }
        else
            last=head=node;
        size++;
    }//头插
    public void popFront() {
        if (size <= 0) {
            System.out.println("无法对空链表做删除");
        }
            head = head.next;
        if (head != null) {

            head.prev = null;
            size--;
        } else {
            last = null;
        }
    }//头删

    public void pushBack(int val) {
        Node node = new Node(val);
        if (last != null) {
            last.next = node;
            node.prev = last;
            last = node;
            size++;
        } else
            head = last = node;
    }//尾插

    public void popBack() {
        if(size<=0) {
            System.out.println("无法对空链表进行删除");
            return;
        }
        if (head == last) {
            head = last = null;
        } else {
            last.prev.next = null;
            last = last.prev;
            size--;
        }
    }//尾删

    public void add(int index, int val) {
        if(index<0||index>size){
            System.out.println("下标越界");
            return;
        }
        if(size==index)
            pushBack(val);//尾插
        else if(size==0)
            pushFront(val);//头插
        else {
            Node cur = head;
            Node node = new Node(val);
            for (int i = 0; i < index; i++) {
                cur = cur.next;
            }
            node.prev = cur.prev;
            node.next = cur;
            node.prev.next = node;
            node.prev = node;
        }
    }// 指定节点插入

    public void remove(int index) {
        if(index<0||index>size){
            System.out.println("下标越界");
            return;
        }
        if(size==index)
            popBack();//尾删
        else if(size==0)
            popFront();//头删
        else {
            Node node = head;
            for (int i = 0; i < index; i++) {
                node = node.next;
            }
            node.next.prev = node.prev;
            node.prev.next = node.next;
            size--;
        }
    }//删除指定下标
    private Node getNode(int index) {
        int len = 0;
        Node p1;//新建一个引用,用来返回指定下标节点
        for (Node cur = head; cur != null; cur = cur.next)
            len++;//求出链表长度
        if(index <=len / 2) {
            p1 = head;
            for (int i = 0; i < index; i++) {
                p1 = p1.next;
            }
        }//下标出现在左半部分,从头开始访问
        else {
            p1 = last;
            for (int i = 0; i < (len - index); i++) {
                p1 = p1.prev;
            }
        }//否则从结尾开始
        return p1;
    }//返回要删除节点
    public static void main(String[] args) {
        MyLinkedList list = new MyLinkedList();
        list.pushFront(1);
        list.pushFront(2);
        list.pushFront(3);
        System.out.println("3 2 1");
        list.popFront();
        list.popFront();
        list.popFront();
        System.out.println("");
        list.pushBack(10);
        list.pushBack(20);
        list.pushBack(30);
        System.out.println("10 20 30");
        list.popBack();
        list.popBack();
        list.popBack();
        System.out.println("");
        list.pushBack(1);
        list.pushBack(2);
        list.pushBack(3);
        list.pushBack(4);
        list.pushBack(5);
        System.out.println("1 2 3 4 5");
        list.add(1, 10);
        System.out.println("1 10 2 3 4 5");
        list.add(5, 20);
        System.out.println("1 10 2 3 4 20 5");
        list.remove(1);
        System.out.println("1 2 3 4 20 5");
        list.remove(4);
        System.out.println("1 2 3 4 5");
    }
}





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转载自blog.csdn.net/weixin_44919969/article/details/97618426
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