jaxb想直接解析出list对象， 不用在list对象上再去包装一层对象
首先定义一个通用的包装对象
<pre>
import java.util.*;
import javax.xml.bind.annotation.XmlAnyElement;
public class Wrapper<T> {
private List<T> items;
public Wrapper() {
items = new ArrayList<T>();
}
public Wrapper(List<T> items) {
this.items = items;
}
@XmlAnyElement(lax=true)
public List<T> getItems() {
return items;
}
}
</pre>
然后是我们的xml
<pre>
<?xml version="1.0" encoding="UTF-8"?>
<Items>
<Item item="Check patient name, gender, age" needData="true" >
<Book name="book1" />
<Book name="book2" />
</Item>
<Item item="Check patient name, gender, age" needData="true" >
<Book name="book1" />
<Book name="book2" />
</Item>
</Items>
</pre>
java类
<pre>
@XmlRootElement(name="Item")
public class Item {
private String item;
private boolean needData;
private List<Book> books;
@XmlAttribute(name = "item")
public String getItem() {
return item;
}
public void setItem(String item) {
this.item = item;
}
@XmlAttribute(name = "needData")
public boolean isNeedData() {
return needData;
}
public void setNeedData(boolean needData) {
this.needData = needData;
}
@XmlElements(value = { @XmlElement(name = "Book", type = Book.class) })
public List<Book> getBooks() {
return books;
}
public void setBooks(List<Book> books) {
this.books = books;
}
}
@XmlRootElement(name="Book")
public class Book {
private String name;
@XmlAttribute(name = "name")
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
</pre>
jaxb代码
<pre>
private static <T> List<T> unmarshal(javax.xml.bind.Unmarshaller unmarshaller,
Class<T> clazz, String xmlLocation) throws JAXBException {
StreamSource xml = new StreamSource(xmlLocation);
Wrapper<T> wrapper = (Wrapper<T>) unmarshaller.unmarshal(xml,
Wrapper.class).getValue();
return wrapper.getItems();
}
public static <T> List parseXmlToList(Class<T> topLevelClass, String xmlLocation) throws Exception {
JAXBContext jc = JAXBContext.newInstance(Wrapper.class,topLevelClass);
// Unmarshal
Unmarshaller unmarshaller = jc.createUnmarshaller();
List<T> list = unmarshal(unmarshaller, topLevelClass, xmlLocation);
return list;
}
</pre>
最后是客户端代码
<pre>
List<Item> addresses = parseXmlToList(Item.class, "WardCheck.xml");
System.out.println(addresses);
System.out.println(addresses.get(0).getItem());
List<Book> list = addresses.get(0).getBooks();
System.out.println(list.size());
System.out.println(addresses.get(0).getBooks().get(0).getName());
</pre>
来自link http://blog.bdoughan.com/2012/11/creating-generic-list-wrapper-in-jaxb.html