冒泡排序也可以写出一些花样

场景

  • 冒泡排序是简单的算法, 但是还是有些花样的
    • 原理: 单趟扫描交换使最后一个元素永远是最大的, 扫描知到不需要发生交换
    • 花样: 单趟扫描算法返回true表示剩下元素都是排过序的, 不需要继续循环

算法主体

// 单趟扫描交换算法主体算法
template<typename T>
bool bubble(T &numbers, RANK low, RANK high) {
    bool sort = true;
    while (++low < high) {
        if (numbers[low - 1] > numbers[low]) {
            sort = false;
            swap(numbers[low], numbers[low - 1]);
        }
    }
    return sort;
};

// 冒泡排序 [low, high)之间的元素进行排序
template<typename T>
vector<T> bubbleSort(vector<T> numbers, RANK low, RANK high) {
    if (low < 0 || low > high || high > numbers.size()) {
        throw new exception();
    }

    while (!bubble(numbers, low, high--));
    return numbers;
};

运行例子

#include <iostream>
#include <vector>

using namespace std;

typedef int RANK;
typedef int T;

#define AGE_MIN 15
#define AGE_MAX 25
#define AGE_SIZE 10
#define STATUS_ERROR -1

// 15 25之间的年龄
RANK getRandomAges() {
    return AGE_MIN + rand() % (AGE_MAX - AGE_MIN);
}

// 打印向量
void showAges(vector<T> ages) {
    for (int i = 0; i < ages.size(); ++i) {
        cout << " ages[" << i << "]=" << ages[i] << endl;
    }
    cout << "向量打印结束" << endl;
};

// 单趟扫描交换算法主体算法
template<typename T>
bool bubble(T &numbers, RANK low, RANK high) {
    bool sort = true;
    while (++low < high) {
        if (numbers[low - 1] > numbers[low]) {
            sort = false;
            swap(numbers[low], numbers[low - 1]);
        }
    }
    return sort;
};

// 冒泡排序 [low, high)之间的元素进行排序
template<typename T>
vector<T> bubbleSort(vector<T> numbers, RANK low, RANK high) {
    if (low < 0 || low > high || high > numbers.size()) {
        throw new exception();
    }

    while (!bubble(numbers, low, high--));
    return numbers;
};


// 输出字符串
void print(string message) {
    cout << message << endl;
}

int main() {
    vector<RANK> ages;
    for (int i = 0; i < AGE_SIZE; ++i) {
        ages.push_back(getRandomAges());
    }

    showAges(ages);
    print("开始排序");
    ages = bubbleSort(ages, 0, ages.size());
    print("结束排序");

    showAges(ages);
    return 0;
}
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转载自blog.csdn.net/cominglately/article/details/103949298