APIView请求生命周期

A作业（必做）

"""
1、整理今天所学知识点

2、简单过过请求模块的源码流程，建立一个视图类，完成一项渲染模块与解析模块的全局局部配置

3、在自己项目中自定义一下异常处理函数，并配置给项目
"""

from rest_framework.parsers import JSONParser,FormParser,MultiPartParser
from rest_framework.renderers import JSONRenderer
from rest_framework.renderers import BrowsableAPIRenderer
from rest_framework.views import APIView
from rest_framework.response import Response

class Student(APIView):
    parser_classes = [JSONParseer]   
    renderer_classes = [JSONRenderer] 
    
    def get(self,request,*args,**kwargs):
        return Response('drf get ok')

    def post(self,request,*args,**kwargs):
        return Response('drf post ok')
from rest_framework.views import exception_handler as drf_exception_handler
from rest_framework.response import Response
from rest_framework import status  

def exception_handler(exc, context):     
    response = drf_exception_handler(exc, context)
    detail = '%s-%s-%s' %(context.get('view'),context.get('request'),exc)
    if not response:  
        response = Response({'detail':detail},, status=status.HTTP_500_INTERNAL_SERVER_ERROR, exception=True)
    else:
        response.data = {'detail':detail}
    return response
urls.py:
    from django.conf.urls import url, include
    from django.contrib import admin

    urlpatterns = [
        url(r'^admin/', admin.site.urls),
        url(r'^api/', include('api.urls')),
    ]

api.urls.py:
    
    from django.conf.urls import url
    from . import  views
    urlpatterns = {
        url(r'^student/$',views.Student.as_view()),
    }

B作业（选做）

"""
1、预习视频

2、后期项目会出现大量的响应，响应数据可以如下
正确的：Response({'status':0,'msg':'ok','results':[]})
异常的：Response({'status':1,'msg':'error'}, status=400)
...

能不能二次封装Response类(自定义一个APIResponse类继承Response)，优化响应
正确的：APIResponse('results'=[])  # 数据状态码和状态信息有默认值，可以不传
异常的：Response(1,'error', status=400)  # 可以按位传数据状态码和状态信息，错误时还可以设置网络状态码
封装后的响应与封装前的响应结果一致，但是大大简化了响应写法
"""