#爬取网页的通用代码框架
import requests
def getHTMLText(url):
try:
r = requests.get(url,timeout=30)
r.raise_for_status() #如果状态不是200,引发HTTPError异常
r.encoding = r.apparent_encoding
return r.text
except:
return "产生异常"
if __name__ == "__main__":
url = "http://www.baidu.com"
print(getHTMLText(url))