n = int(input())
a = []
dic = {0:0,1:0,2:0,3:0,4:0}
for i in range(n):
a.append(list(map(int,input().split())))
for j in a:
count = 4
temp1 = [j[0],j[1]+1]
temp2 = [j[0]+1,j[1]]
temp3 = [j[0],j[1]-1]
temp4 = [j[0]-1,j[1]]
temp5 = [j[0]-1,j[1]+1]
temp6 = [j[0]+1,j[1]+1]
temp7 = [j[0]+1,j[1]-1]
temp8 = [j[0]-1,j[1]-1]
if temp1 in a and temp2 in a and temp3 in a and temp4 in a:
if temp5 not in a:
count -= 1
if temp6 not in a:
count -= 1
if temp7 not in a:
count -= 1
if temp8 not in a:
count -= 1
dic[count] += 1
for i in range(5):
print(dic[i])
[Python]CCF——第18次CCF认证题2(201912-2)
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转载自www.cnblogs.com/SavvyM/p/12053390.html
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