oracle 查询两个字段值相同的记录

select A.* from tb_mend_enrol A,
                (select A.Typeid, A.address from tb_mend_enrol A
                  group by A.Typeid, A.address
                  having count(A.Typeid) >= 2 and count(A.address) >= 2 ) B
where A.Typeid = B.Typeid  and A.address = B.address and a.reporter='测试' 
and A.reptime >= to_date('2018-08-01 00:00:00','YYYY-MM-DD HH24:MI:SS')
order by A.Address, A.reptime


方法二:

select A.* from tb_mend_enrol A
where (select count(*) from tb_mend_enrol A1
where A1.Typeid = A.Typeid and A1.address=A.address)>1
and a.reporter='测试'
and A.reptime >= to_date('2018-08-01 00:00:00','YYYY-MM-DD HH24:MI:SS'
order by A.Address

  

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转载自www.cnblogs.com/wmxblog/p/11936698.html