需求:已知字符串为一数字字符形式,多为float,double转换过来,将其后多余的0与.去掉.
package test; public class TestString { public static void main(String[] args) { Float f = 1f; System.out.println(f.toString());//1.0 System.out.println(subZeroAndDot("1"));; // 转换后为1 System.out.println(subZeroAndDot("10"));; // 转换后为10 System.out.println(subZeroAndDot("1.0"));; // 转换后为1 System.out.println(subZeroAndDot("1.010"));; // 转换后为1.01 System.out.println(subZeroAndDot("1.01"));; // 转换后为1.01 } public static String subZeroAndDot(String s){ if(s.indexOf(".") > 0){ s = s.replaceAll("0+?$", "");//去掉多余的0 s = s.replaceAll("[.]$", "");//如最后一位是.则去掉 } return s; } }