根据查询结果值显示结果

SELECT 
CURDATE() AS '日期',
(CASE tableA.gender
WHEN '0' THEN ''
WHEN '1' THEN ''
ELSE DATE_SUB(CURDATE(),INTERVAL 1 DAY)
END
) AS '性别,
FROM tableA

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转载自www.cnblogs.com/stuka/p/11798345.html
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