数据库操作练习一

查看岗位是teacher的员工姓名、年龄
1. 查看岗位是teacher且年龄大于30岁的员工姓名、年龄
2. 查看岗位是teacher且薪资在9000-1000范围内的员工姓名、年龄、薪资
3. 查看岗位描述不为NULL的员工信息
4. 查看岗位是teacher且薪资是10000或9000或30000的员工姓名、年龄、薪资
5. 查看岗位是teacher且薪资不是10000或9000或30000的员工姓名、年龄、薪资
6. 查看岗位是teacher且名字是jin开头的员工姓名、年薪

先创建表格slt：

mysql> create table slt(
    -> num int auto_increment primary key,
    -> name char(10),
    -> job char(10),
    -> age int,
    -> salary int,
    -> descrip char(128)not null default ''
    -> )charset=utf8;

查看列表

mysql> desc slt;
+---------+-----------+------+-----+---------+----------------+
| Field   | Type      | Null | Key | Default | Extra          |
+---------+-----------+------+-----+---------+----------------+
| num     | int(11)   | NO   | PRI | NULL    | auto_increment |
| name    | char(10)  | YES  |     | NULL    |                |
| job     | char(10)  | YES  |     | NULL    |                |
| age     | int(11)   | YES  |     | NULL    |                |
| salary  | int(11)   | YES  |     | NULL    |                |
| descrip | char(128) | NO   |     |    |                |
+---------+-----------+------+-----+---------+----------------+
6 rows in set (0.02 sec)

此时表为空

mysql> select * from slt;
Empty set (0.00 sec)

插入数据：

mysql> insert into tlt(name, job, age, salary,descrip) values
    -> ('Tom',   'teacher',    30,      20000,  level2  ),
    -> ('frank',    'teacher'， 31,  21000,  level2  ),
    -> ('jack',  'teacher',     32,  22000,     level2  ),
    -> ('jhon',     'asistant', 23, 8000,    '' ),
    -> ('hugo',     'manager',  45,     30000,  level4  ),
    -> ('jinhisan',     'teacher',  26,     9000,   level1  )
    -> ;
Query OK, 6 row affected (0.01 sec)

1、查看岗位是teacher的员工姓名、年龄

mysql> select distinct name, age from slt where job='teacher';

2、查看岗位是teacher且年龄大于30岁的员工姓名、年龄

mysql> select distinct name, age from slt where job='teacher' and age>30;

3、查看岗位是teacher且薪资在1000-9000范围内的员工姓名、年龄、薪资

mysql> select distinct name, age, salary from slt where job='teacher' and (salary>1000 and salary<9000);

4、查看岗位描述不为NULL的员工信息

mysql> select * from slt where descrip!=NULL ;

5、查看岗位是teacher且薪资是10000或9000或30000的员工姓名、年龄、薪资

mysql> select distinct name, age, salary from slt where job='teacher' and (salary=10000 or salary=9000 or salary=30000);

6、查看岗位是teacher且薪资不是10000或9000或30000的员工姓名、年龄、薪资

mysql> select distinct name, age, salary from slt where job='teacher' and (salary not in (10000,9000,30000));

7、查看岗位是teacher且名字是'jin'开始的员工姓名、年薪

mysql> select * from slt where job='teacher' and name like 'jin%' ;

数据库操作 练习一

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