python -- 找出列表list中的重复元素

转载:https://blog.csdn.net/August1226/article/details/82144759

【问题解决】

from collections import Counter #引入Counter
a = [29,36,57,12,79,43,23,56,28,11,14,15,16,37,24,35,17,24,33,15,39,46,52,13]
b = dict(Counter(a))
print ([key for key,value in b.items()if value > 1]) #只展示重复元素
print ({key:value for key,value in b.items()if value > 1}) #展现重复元素和重复次数
测试结果展示:

 

完成! 

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转载自www.cnblogs.com/wsnan/p/11670851.html