1、表架构
student(sid,sname,sage,ssex) 学生表
course(cid,cname,tid) 课程表
sC(sid,cid,score) 成绩表
teacher(tid,tname) 教师表
2、建表sql语句
1 CREATE TABLE student 2 ( 3 sid INT PRIMARY KEY NOT NULL, 4 sname VARCHAR(30), 5 sage INT, 6 ssex VARCHAR(8) 7 ) 8 9 CREATE TABLE course 10 ( 11 cid INT PRIMARY KEY NOT NULL, 12 cname VARCHAR(30), 13 tid INT 14 ) 15 16 CREATE TABLE sc 17 ( 18 sid INT NOT NULL, 19 cid INT NOT NULL, 20 score INT 21 ) 22 23 CREATE TABLE teacher 24 ( 25 tid INT PRIMARY KEY NOT NULL, 26 tname VARCHAR(30) 27 )
3、问题:
(1)查询“30001”课程的所有学生的学号与分数;
SELECT sid,score FROM sc WHERE cid="30001"
(2)查询“001”课程比“002”课程成绩高的所有学生的学号与分数;
SELECT a.sid,a.score FROM (SELECT sid,score FROM sc WHERE cid="30001") a, (SELECT sid,score FROM sc WHERE cid="30002") b WHERE a.score>b.score AND a.sid=b.sid
(3)查询平均成绩大于60分的同学的学号和平均成绩;
SELECT sid,AVG(score) FROM sc GROUP BY sid HAVING AVG(score)>60
(4)查询所有同学的学号、姓名、选课数、总成绩
SELECT s.sid AS "学号", s.sname AS "姓名", COUNT(sc.cid) AS "课程数目", SUM(sc.score) AS "总分数" FROM student s, sc sc WHERE s.sid=sc.sid GROUP BY s.sid
(5)查询姓“李”的老师的个数;
select count(distinct(Tname)) from teacher where tname like '李%';
(6)查询学过“张三”老师课的同学的学号、姓名
SELECT s.sid AS "学号", s.sname AS "姓名" FROM student s, sc sc, course c, teacher t WHERE s.sid=sc.sid AND c.cid=sc.cid AND t.tid=c.tid AND t.tname="张三"
(7)查询没有学过“张三”老师课的同学的学号、姓名
SELECT s.sid, s.sname FROM student s WHERE s.sid NOT IN ( SELECT s.sid FROM student s, sc sc, course c, teacher t WHERE s.sid=sc.sid AND c.cid=sc.cid AND t.tid=c.tid AND t.tname="张三" )