NumPy笔记：numpy与python原生数组计算效率比较

import numpy as np
import random
import time
a = []
for i in range(10000000):
    a.append(random.random())
# list
t1 = time.time()
sum1 = sum(a)
t2 = time.time()
print("time_list:", (t2-t1))
# numpy
b = np.array(a)
t3 = time.time()
sum2 = np.sum(b)
t4 = time.time()
print("time_numpy:", t4-t3)
 

time_list: 0.07811212539672852
time_numpy: 0.015620231628417969