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➤微信公众号:为敢(WeiGanTechnologies)
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➤原文地址:https://www.cnblogs.com/strengthen/p/11443478.html
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With respect to a given puzzle
string, a word
is valid if both the following conditions are satisfied:
word
contains the first letter ofpuzzle
.- For each letter in
word
, that letter is inpuzzle
.
For example, if the puzzle is "abcdefg", then valid words are "faced", "cabbage", and "baggage"; while invalid words are "beefed" (doesn't include "a") and "based" (includes "s" which isn't in the puzzle).
Return an array answer
, where answer[i]
is the number of words in the given word list words
that are valid with respect to the puzzle puzzles[i]
.
Example :
Input: words = ["aaaa","asas","able","ability","actt","actor","access"], puzzles = ["aboveyz","abrodyz","abslute","absoryz","actresz","gaswxyz"] Output: [1,1,3,2,4,0] Explanation: 1 valid word for "aboveyz" : "aaaa" 1 valid word for "abrodyz" : "aaaa" 3 valid words for "abslute" : "aaaa", "asas", "able" 2 valid words for "absoryz" : "aaaa", "asas" 4 valid words for "actresz" : "aaaa", "asas", "actt", "access" There're no valid words for "gaswxyz" cause none of the words in the list contains letter 'g'.
Constraints:
1 <= words.length <= 10^5
4 <= words[i].length <= 50
1 <= puzzles.length <= 10^4
puzzles[i].length == 7
words[i][j]
,puzzles[i][j]
are English lowercase letters.- Each
puzzles[i]
doesn't contain repeated characters.
外国友人仿照中国字谜设计了一个英文版猜字谜小游戏,请你来猜猜看吧。
字谜的迷面 puzzle
按字符串形式给出,如果一个单词 word
符合下面两个条件,那么它就可以算作谜底:
- 单词
word
中包含谜面puzzle
的第一个字母。 - 单词
word
中的每一个字母都可以在谜面puzzle
中找到。
例如,如果字谜的谜面是 "abcdefg",那么可以作为谜底的单词有 "faced", "cabbage", 和 "baggage";而 "beefed"(不含字母 "a")以及 "based"(其中的 "s" 没有出现在谜面中)。
返回一个答案数组 answer
,数组中的每个元素 answer[i]
是在给出的单词列表 words
中可以作为字谜迷面 puzzles[i]
所对应的谜底的单词数目。
示例:
输入: words = ["aaaa","asas","able","ability","actt","actor","access"], puzzles = ["aboveyz","abrodyz","abslute","absoryz","actresz","gaswxyz"] 输出:[1,1,3,2,4,0] 解释: 1 个单词可以作为 "aboveyz" 的谜底 : "aaaa" 1 个单词可以作为 "abrodyz" 的谜底 : "aaaa" 3 个单词可以作为 "abslute" 的谜底 : "aaaa", "asas", "able" 2 个单词可以作为 "absoryz" 的谜底 : "aaaa", "asas" 4 个单词可以作为 "actresz" 的谜底 : "aaaa", "asas", "actt", "access" 没有单词可以作为 "gaswxyz" 的谜底,因为列表中的单词都不含字母 'g'。
提示:
1 <= words.length <= 10^5
4 <= words[i].length <= 50
1 <= puzzles.length <= 10^4
puzzles[i].length == 7
words[i][j]
,puzzles[i][j]
都是小写英文字母。- 每个
puzzles[i]
所包含的字符都不重复。