1、使用while循环输入:1 2 3 4 5 6 8 9 10
count = 0
while count< 10:
count=count+1
if count == 7:
pass
else:
print(count)
2、求1-100的所有数的和
count = 0
sum=0
while count < 101:
sum=count+sum
count=count+1
if count>=101:
print(sum)
3、输出1-100内的所有奇数
count = 0
while count < 101:
count=count+1
n=count % 2
if n==0:
pass
else:
print(count)
4、输出1-100内所有偶数
count = 0
while count < 101:
count=count+1
n=count % 2
if n!=0:
pass
else:
print(count)
5、求1-2+3-4+5...99的所有数的和
6、用户登录(三次机会重试)