spring-aop的坑

一、配置文件

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:context="http://www.springframework.org/schema/context" 
    xmlns:aop="http://www.springframework.org/schema/aop" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="
    http://www.springframework.org/schema/beans 
    http://www.springframework.org/schema/beans/spring-beans-3.2.xsd 
    http://www.springframework.org/schema/context
    http://www.springframework.org/schema/context/spring-context-3.2.xsd 
    http://www.springframework.org/schema/aop
    http://www.springframework.org/schema/aop/spring-aop-3.2.xsd 
    ">
    
    <!-- 需要注入的对象 -->    
    <bean id="goodsProcess" class="com.wl.service.GoodsProcess"></bean>
    <!-- 额外内容 -->
    <bean id="afterLogAdvice" class="com.wl.advices.AfterLogAdvice"></bean>
    
    <!-- 定义切点 -->
    <aop:config>
        <aop:pointcut expression="execution(* com.wl.service..*.*(String,..))" id="pct"/>
        <aop:advisor advice-ref="afterLogAdvice" pointcut-ref="pct"/>
    </aop:config>
</beans>

二、被扫描的类（注意这个类不能继承接口，不然aop会失效）

package com.wl.service;

public class GoodsProcess {
    public void addUser(String name,String mobile){
        System.out.println("add user");
    }
    
    public void modifyUser(String name){
        System.out.println("modify user");
    }
    
    public void removeUser(Integer id){
        System.out.println("remove user");
    }
}

三、测试

package com.wl.test;

import org.junit.Test;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import com.wl.service.GoodsProcess;

public class Demo_test {    
    
    @Test
    public void testLog() {
        @SuppressWarnings("resource")
        ClassPathXmlApplicationContext cxt = new ClassPathXmlApplicationContext("spring-context.xml");
        GoodsProcess goodsDao = (GoodsProcess) cxt.getBean("goodsProcess");
        goodsDao.modifyUser("ddd");    
    }
}

四、结果

　　作者：醉烟

　　出处：https://www.cnblogs.com/WangLei2018/

　　本文版权归作者和博客园共有，欢迎转载，但未经作者同意必须保留此段声明，且在文章页面明显位置给出原文连接，否则保留追究法律责任的权利。