解题报告 『[SHOI2015]脑洞治疗仪(ODT)』

原题地址

继续用珂朵莉树水题。

 

代码实现如下:

#include <bits/stdc++.h>
using namespace std;
#define int long long
#define IT set<node>::iterator
#define rep(i, a, b) for (register int i = (a); i <= (b); i++)

int n, m;

struct node {
    int l, r;
    mutable int v;
    node(int L, int R = -1, int V = 0): l(L), r(R), v(V) {}
    int operator <(const node &o) const {
        return l < o.l;
    }
};

set<node> s;

int MAX(int a, int b) {return a > b ? a : b;}

int read() {
    int x = 0, flag = 0;
    char ch = ' ';
    while (ch != '-' && (ch < '0' || ch > '9')) ch = getchar();
    if (ch == '-') {
        flag = 1;
        ch = getchar();
    }
    while (ch >= '0' && ch <= '9') {
        x = (x << 1) + (x << 3) + (ch ^ '0');
        ch = getchar();
    }
    return flag ? -x : x;
}

IT split(int pos) {
    IT it = s.lower_bound(node(pos));
    if (it != s.end() && it->l == pos) return it;
    it--;
    int L = it->l, R = it->r, V = it->v;
    s.erase(it);
    s.insert(node(L, pos - 1, V));
    return s.insert(node(pos, R, V)).first;
}

void assign(int l, int r, int val) {
    IT itr = split(r + 1), itl = split(l);
    s.erase(itl, itr);
    s.insert(node(l, r, val));
}

int sum(int l, int r) {
    IT itr = split(r + 1), itl = split(l);
    int ans = 0;
    while (itl != itr) {
        ans += itl->v ? itl->r - itl->l + 1 : 0;
        itl++;
    }
    return ans;
}

void repair(int l, int r, int num) {
    IT itr = split(r + 1), itl = split(l);
    while (itl != itr) {
        if (!num) return;
        if (!(itl->v)) {
            int end = 0, len = itl->r - itl->l + 1;
            if (len > num) {
                end = itl->l + num - 1;
                num = 0;
                assign(itl->l, end, 1);
            }
            else {
                num -= len;
                itl->v = 1;
            }
        }
        itl++;
    }
}

int calc(int l, int r) {
    IT itr = split(r + 1), itl = split(l);
    int ans = 0, now = 0;
    while (itl != itr) {
        if (itl->v) {
            ans = MAX(ans, now);
            now = 0;
        }
        else now += itl->r - itl->l + 1;
        itl++;
    }
    return MAX(ans, now);
}

void write(int x) {
    if (x < 0) {
        putchar('-');
        x = -x;
    }
    if (x > 9) write(x / 10);
    putchar(x % 10 + '0');
}

signed main() {
    n = read(), m = read();
    s.insert(node(1, n, 1));
    s.insert(node(n + 1, n + 1, 0));
    rep(i, 1, m) {
        int a, b, l, r, opt;
        opt = read(), l = read(), r = read();
        if (!opt) assign(l, r, 0);
        else if (opt == 1) {
            a = read(), b = read();
            int num = sum(l, r);
            assign(l, r, 0);
            repair(a, b, num);
        }
        else {
            write(calc(l, r));
            printf("\n");
        }
    } 
    return 0;
}
View Code

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转载自www.cnblogs.com/Kirisame-Marisa/p/11364413.html
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