[Swift]LeetCode1152. 用户网站访问行为分析 | Analyze User Website Visit Pattern

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You are given three arrays usernametimestamp and website of the same length N where the ithtuple means that the user with name username[i] visited the website website[i] at time timestamp[i].

3-sequence is a list of not necessarily different websites of length 3 sorted in ascending order by the time of their visits.

Find the 3-sequence visited at least once by the largest number of users. If there is more than one solution, return the lexicographically minimum solution.

A 3-sequence X is lexicographically smaller than a 3-sequence Y if X[0] < Y[0] or X[0] == Y[0] and (X[1] < Y[1] or X[1] == Y[1] and X[2] < Y[2])

It is guaranteed that there is at least one user who visited at least 3 websites. No user visits two websites at the same time.

Example 1:

Input: username = ["joe","joe","joe","james","james","james","james","mary","mary","mary"], timestamp = [1,2,3,4,5,6,7,8,9,10], website = ["home","about","career","home","cart","maps","home","home","about","career"]
Output: ["home","about","career"]
Explanation: 
The tuples in this example are:
["joe", 1, "home"]
["joe", 2, "about"]
["joe", 3, "career"]
["james", 4, "home"]
["james", 5, "cart"]
["james", 6, "maps"]
["james", 7, "home"]
["mary", 8, "home"]
["mary", 9, "about"]
["mary", 10, "career"]
The 3-sequence ("home", "about", "career") was visited at least once by 2 users.
The 3-sequence ("home", "cart", "maps") was visited at least once by 1 user.
The 3-sequence ("home", "cart", "home") was visited at least once by 1 user.
The 3-sequence ("home", "maps", "home") was visited at least once by 1 user.
The 3-sequence ("cart", "maps", "home") was visited at least once by 1 user.

Note:

  1. 3 <= N = username.length = timestamp.length = website.length <= 50
  2. 1 <= username[i].length <= 10
  3. 0 <= timestamp[i] <= 10^9
  4. 1 <= website[i].length <= 10
  5. Both username[i] and website[i] contain only lowercase characters.

为了评估某网站的用户转化率,我们需要对用户的访问行为进行分析,并建立用户行为模型。日志文件中已经记录了用户名、访问时间 以及 页面路径。

为了方便分析,日志文件中的 N 条记录已经被解析成三个长度相同且长度都为 N 的数组,分别是:用户名 username,访问时间 timestamp 和 页面路径 website。第 i 条记录意味着用户名是 username[i] 的用户在 timestamp[i] 的时候访问了路径为 website[i] 的页面。

我们需要找到用户访问网站时的 『共性行为路径』,也就是有最多的用户都 至少按某种次序访问过一次 的三个页面路径。需要注意的是,用户 可能不是连续访问 这三个路径的。

『共性行为路径』是一个 长度为 3 的页面路径列表,列表中的路径 不必不同,并且按照访问时间的先后升序排列。

如果有多个满足要求的答案,那么就请返回按字典序排列最小的那个。(页面路径列表 X 按字典序小于 Y 的前提条件是:X[0] < Y[0] 或 X[0] == Y[0] 且 (X[1] < Y[1] 或 X[1] == Y[1] 且 X[2] < Y[2])

题目保证一个用户会至少访问 3 个路径一致的页面,并且一个用户不会在同一时间访问两个路径不同的页面。

示例:

输入:username = ["joe","joe","joe","james","james","james","james","mary","mary","mary"], timestamp = [1,2,3,4,5,6,7,8,9,10], website = ["home","about","career","home","cart","maps","home","home","about","career"]
输出:["home","about","career"]
解释:
由示例输入得到的记录如下:
["joe", 1, "home"]
["joe", 2, "about"]
["joe", 3, "career"]
["james", 4, "home"]
["james", 5, "cart"]
["james", 6, "maps"]
["james", 7, "home"]
["mary", 8, "home"]
["mary", 9, "about"]
["mary", 10, "career"]
有 2 个用户至少访问过一次 ("home", "about", "career")。
有 1 个用户至少访问过一次 ("home", "cart", "maps")。
有 1 个用户至少访问过一次 ("home", "cart", "home")。
有 1 个用户至少访问过一次 ("home", "maps", "home")。
有 1 个用户至少访问过一次 ("cart", "maps", "home")。

提示:

  1. 3 <= N = username.length = timestamp.length = website.length <= 50
  2. 1 <= username[i].length <= 10
  3. 0 <= timestamp[i] <= 10^9
  4. 1 <= website[i].length <= 10
  5. username[i] 和 website[i] 都只含小写字符

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转载自www.cnblogs.com/strengthen/p/11333856.html