【JavaWeb】jQuery对Ajax的支持

jQuery对Ajax的支持

jQuery对Ajax进行封装，提供了$.ajax()方法
语法：$.ajax(options)

常用设置项	说明
url	发送请求地址
type	请求类型get\|post
data	向服务器传递的参数
dataType	服务器响应的数据类型 text\|json\|xml\|html\|jsonp\|script
success	接收响应时的处理函数
error	请求失败时的处理函数

实例代码

MusicServlet.java

package demo;

import java.io.IOException;
import java.util.ArrayList;
import java.util.List;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import com.alibaba.fastjson.JSON;

/**
 * Servlet implementation class MusicSetvlet
 */
@WebServlet("/music")
public class MusicServlet extends HttpServlet {
    private static final long serialVersionUID = 1L;
       
    /**
     * @see HttpServlet#HttpServlet()
     */
    public MusicServlet() {
        super();
        // TODO Auto-generated constructor stub
    }

    /**
     * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        String songType = request.getParameter("songType");
        System.out.println(songType);
        List<String> song = new ArrayList<>();
        if(songType.equals("流行歌曲")) {
            song.add("稻香");
            song.add("晴天");
            song.add("告白气球");
        }else if(songType.equals("经典歌曲")) {
            song.add("千千阙歌");
            song.add("傻女");
            song.add("七友");
        }else if(songType.equals("摇滚歌曲")) {
            song.add("一块红布");
            song.add("假行僧");
            song.add("星长征路上的摇滚");
        }
        String json = JSON.toJSONString(song);
        response.setContentType("text/html;charset=utf-8");
        response.getWriter().println(json);
    }

}

musicList.java

<%@ page language="java" contentType="text/html; charset=utf-8"
    pageEncoding="utf-8"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Insert title here</title>
<style>
div {
    text-align: center;
}

.mystyle {
    width: 30%;
    cursor: pointer;
}
</style>
</head>
<body>
    <div>
        <input class="mystyle" type="button" value="流行歌曲"> <input
            class="mystyle" type="button" value="经典歌曲"> <input
            class="mystyle" type="button" value="摇滚歌曲">
    </div>
    <div id="divContent"></div>
    <script type="text/javascript" src="js/jquery-3.4.1.js"></script>
    <script type="text/javascript">
        $(":button").click(function() {
            var songType = this.value;
            $(function() {
                $.ajax({
                    "url" : "/ajax/music",
                    "type" : "get",
                    "data" : {
                        "songType" : songType
                    },
                    "dataType" : "json",
                    "success" : function(json) {
                        $("#divContent>span").remove();
                        $("#divContent>br").remove();
                        for (var i = 0; i < json.length; i++) {
                            var html = "<span>" + json[i] + "</span><br>";
                            $("#divContent").append(html);
                        }
                    }

                })
            })
        })
    </script>
</body>
</html>

【JavaWeb】jQuery对Ajax的支持

jQuery对Ajax的支持

实例代码

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