Codeforces1144A(A题）Diverse Strings

A. Diverse Strings

A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", "xyz", "r" and "dabcef". The following string are not diverse: "az", "aa", "bad" and "babc". Note that the letters 'a' and 'z' are not adjacent.

Formally, consider positions of all letters in the string in the alphabet. These positions should form contiguous segment, i.e. they should come one by one without any gaps. And all letters in the string should be distinct (duplicates are not allowed).

You are given a sequence of strings. For each string, if it is diverse, print "Yes". Otherwise, print "No".

Input

The first line contains integer nn (1≤n≤1001≤n≤100), denoting the number of strings to process. The following nn lines contains strings, one string per line. Each string contains only lowercase Latin letters, its length is between 11 and 100100, inclusive.

Output

Print n

代码：

 1 #include<iostream>
 2 #include<algorithm>
 3 #include<cstring>
 4 using namespace std;
 5 int main() {
 6     int n;
 7     bool flag=true;
 8     cin>>n;
 9     while(n--) {
10         char s[1000];
11         int a[1000];
12         cin>>s;
13         int len=strlen(s);
14         for (int i = 0; i < len; i++) {
15             a[i]=s[i]-'0';
16         }
17         sort(a,a+len);
18         for(int i=0; i<len-1; i++) {
19             if((a[i+1]-a[i])!=1) {
20                 flag=false;
21                 break;
22             }
23         }
24         if(flag) {
25             cout<<"Yes"<<endl;
26         } else {
27             cout<<"No"<<endl;
28         }
29         flag=true;
30     }
31 }

思路分析：对字符转整数排序，要是差不为1就输出no,否则输出yes。

题目链接：https://codeforces.com/contest/1144/problem/A