python 按多维列表中的某一个元素位进行排序

import os,re

top = os.popen("tasklist")

process_list = []

split_r = r"\s+"


memory_topTen = []

for key,item in enumerate(top):
item = str(item).rstrip("\n")

if key not in [0,1,2]:
result = re.split(split_r,item)
if len(result)== 6:
memory_topTen.append(result)

# print(memory_topTen)

# 获取列表第5个元素
def takeSecond(elem):
return elem[4]

memory_topTen.sort(key= takeSecond,reverse=True)

memory_topTen = memory_topTen[0:10]

for item in memory_topTen:
print(item)




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转载自www.cnblogs.com/leigepython/p/11242335.html