js base64解密

decode (input) {
var _keyStr = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/='
var output = ''
var chr1, chr2, chr3
var enc1, enc2, enc3, enc4
var i = 0
var re = /[^A-Za-z0-9\+\/\=]/g;
input = input.replace(re, '')
while (i < input.length) {
enc1 = _keyStr.indexOf(input.charAt(i++))
enc2 = _keyStr.indexOf(input.charAt(i++))
enc3 = _keyStr.indexOf(input.charAt(i++))
enc4 = _keyStr.indexOf(input.charAt(i++))
chr1 = (enc1 << 2) | (enc2 >> 4)
chr2 = ((enc2 & 15) << 4) | (enc3 >> 2)
chr3 = ((enc3 & 3) << 6) | enc4
output = output + String.fromCharCode(chr1)
if (enc3 !== 64) {
output = output + String.fromCharCode(chr2)
}
if (enc4 !== 64) {
output = output + String.fromCharCode(chr3)
}
}
output = this._utf8_decode(output)
return output
},
_utf8_decode(utftext) {
let string = ''
let i = 0
let c = 0
let c2 = 0
let c3 = 0
while (i < utftext.length) {
c = utftext.charCodeAt(i)
if (c < 128) {
string += String.fromCharCode(c)
i++
} else if ((c > 191) && (c < 224)) {
c2 = utftext.charCodeAt(i + 1)
string += String.fromCharCode(((c & 31) << 6) | (c2 & 63))
i += 2
} else {
c2 = utftext.charCodeAt(i + 1)
c3 = utftext.charCodeAt(i + 2)
string += String.fromCharCode(((c & 15) << 12) | ((c2 & 63) << 6) | (c3 & 63))
i += 3
}
}
return string
},

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转载自www.cnblogs.com/JiaFanFan/p/11236338.html