#!bin/bash
#作者:liusingbon
#功能:判断用户输入的是 Yes 或 NO
read -p "Are you sure?[y/n]:" sure
case $sure in
y|Y|Yes|yes|YES)
echo "you enter $sure";;
n|N|NO|no)
echo "you enter $sure";;
*)
echo "error";;
esac
判断用户输入YES或NO
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转载自www.cnblogs.com/liusingbon/p/11199673.html
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