shell awk匹配字符串

配置文件

config.properties 

xxx_yyy_lib_path="路径"

xxx_yyy_bin_path="路径"

想通过shell来读入路径，shell中需要附带2个变量xxx,yyy

readconfig.sh

#!/bin/bash
source ./config.properties

xxx_declare=$1
yyy_declare=$2

lib_path=`cat config.properties | awk -F'=' "/${xxx_declare}_${yyy_declare}_lib_path" '{ print $2}'`
bin_path=`cat config.properties | awk -F'=' "/${xxx_declare}_${yyy_declare}_bin_path" '{ print $2}'`

echo "lib_path is $lib_path"
echo "bin_path is $bin_path"

还有一个需求，由于xxx是带.的字符串，例如v2.1.0

路径中不能识别 . ,这里我需要通过shell删除 . 得到v210

str=`echo $xxx_declare |sed 's/\.//g'`
echo $str