zedboard将ZYNQ的EMIO映射到PS端串口1使用收发

做了两天ZYNQ的EMIO映射到PS端串口1使用的实验终于成功了,原因竟然是SDK收发程序不适用,先是做了逻辑证明CP2012是可以使用的,现在贴出整个用SDK收发控制EMIO的工程:

先上图:

首先BD:将UART通过EMIO引出来

2、XDC:

set_property IOSTANDARD LVCMOS33 [get_ports UART_1_rxd]
set_property IOSTANDARD LVCMOS33 [get_ports UART_1_txd]
set_property PACKAGE_PIN AB10 [get_ports UART_1_txd]
set_property PACKAGE_PIN AB9 [get_ports UART_1_rxd]

3、导入SDK:

可实现helloword测试程序;

#include <stdio.h>
#include "platform.h"
#include "xil_printf.h"


int main()
{
//    init_platform();//无用

    print("Hello World\n\r");

//    cleanup_platform();//无用
    return 0;
}

 

UART发送数据(未尝试)

设置Tera Term的COM4为波特率9600(匹配上述代码)

设置COM5为波特率115200

UART接收数据

main.c

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* all copies or substantial portions of the Software.
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* in advertising or otherwise to promote the sale, use or other dealings in
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/*
 * helloworld.c: simple test application
 *
 * This application configures UART 16550 to baud rate 9600.
 * PS7 UART (Zynq) is not initialized by this application, since
 * bootrom/bsp configures it to baud rate 115200
 *
 * ------------------------------------------------
 * | UART TYPE   BAUD RATE                        |
 * ------------------------------------------------
 *   uartns550   9600
 *   uartlite    Configurable only in HW design
 *   ps7_uart    115200 (configured by bootrom/bsp)
 */
/*
#include <stdio.h>
#include "platform.h"
#include "xil_printf.h"


int main()
{
    init_platform();
while(1){
    print("Hello World\n\r");
}
    cleanup_platform();
    return 0;
}*/
#include "xparameters.h"
#include "xuartps.h"
#include "xil_printf.h"
#include "sleep.h"

int main()
{
	//使用UART0实现发送数据
	XUartPs Uart_Ps;//uart对象

    //查找uart配置
	XUartPs_Config *Config;
	Config = XUartPs_LookupConfig(XPAR_XUARTPS_0_DEVICE_ID);//ID来源于xparameters.h
	if (Config == NULL)
	{
		//在bsp中设置为uart1负责stdout
		print("failed XUartPs_LookupConfig\n\r");
		return XST_FAILURE;
	}
	else
	{
		print("succeed XUartPs_LookupConfig\n\r");
	}

	//uart初始化
	int Status;
	Status = XUartPs_CfgInitialize(&Uart_Ps, Config, Config->BaseAddress);
	if (Status != XST_SUCCESS)
	{
		print("failed XUartPs_CfgInitialize\n\r");
		return XST_FAILURE;
	}
	else
	{
		print("succeed XUartPs_CfgInitialize\n\r");
	}

	//接收缓冲
	u8 buf[64];

	//接收字节数
	u32 recv_cnt = 0;

	while (TRUE)
	{
		usleep(500000);//等待500ms
		recv_cnt = XUartPs_Recv(&Uart_Ps, buf, 64);//接收数据
		if (recv_cnt > 0)
		{
			//返回接收到的数据
			xil_printf("%s", buf);

			//清空缓冲
			memset(buf, 0, 64);
		}
	}

    return 0;
}

 问题描述参考https://blog.csdn.net/botao_li/article/details/85302027

关于UART接收的一些说明
本实验原本是打算使用通过中断来响应UART数据到达,再使用XUartPs_Recv进行接收,但是无论怎样实验都无法进入中断响应函数。

并且发现来自system.mss里的中断示例程序同样也无法正常进入中断响应函数。


无法确定是不是有一些在Vivado工程或者bsp里的设置不正确导致

根据以往嵌入式程序的开发经验,对于单线程运行的程序而言,持续接收数据如果使用中断来响应接收的话会占用更多的CPU时间(因为保存与重载现场的操作),相比较而言采用轮询的方式可以达成更高的运行效率。对于偶然突发的数据接收,使用中断接收相比较轮询接收,可以实现更快速的响应。
中断函数描述:但是尝试了两天没成功

#include "sys_intr.h"
#include "uartps_intr.h"



void init_intr_sys(void)
{
	Init_UartPsIntr(&UartPs,UART_DEVICE_ID);
	Init_Intr_System(&Intc);
	Setup_Intr_Exception(&Intc);
	UartPs_Setup_IntrSystem(&Intc, &UartPs, UART_INT_IRQ_ID);
}

int main(void)
{

	init_intr_sys();
	XUartPs_Recv(&UartPs, RecvBuffer, TEST_BUFFER_SIZE);
    while(1);
	return 0;
}

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转载自blog.csdn.net/weixin_40640020/article/details/92408688