[Swift]LeetCode1087. 字母切换 | Permutation of Letters

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A string S represents a list of words.

Each letter in the word has 1 or more options.  If there is one option, the letter is represented as is.  If there is more than one option, then curly braces delimit the options.  For example, "{a,b,c}" represents options ["a", "b", "c"].

For example, "{a,b,c}d{e,f}" represents the list ["ade", "adf", "bde", "bdf", "cde", "cdf"].

Return all words that can be formed in this manner, in lexicographical order. 

Example 1:

Input: "{a,b}c{d,e}f"
Output: ["acdf","acef","bcdf","bcef"]

Example 2:

Input: "abcd"
Output: ["abcd"] 

Note:

  1. 1 <= S.length <= 50
  2. There are no nested curly brackets.
  3. All characters inside a pair of consecutive opening and ending curly brackets are different.

我们用一个特殊的字符串 S 来表示一份单词列表,之所以能展开成为一个列表,是因为这个字符串 S 中存在一个叫做「选项」的概念:

单词中的每个字母可能只有一个选项或存在多个备选项。如果只有一个选项,那么该字母按原样表示。

如果存在多个选项,就会以花括号包裹来表示这些选项(使它们与其他字母分隔开),例如 "{a,b,c}" 表示 ["a", "b", "c"]

例子:"{a,b,c}d{e,f}" 可以表示单词列表 ["ade", "adf", "bde", "bdf", "cde", "cdf"]

请你按字典顺序,返回所有以这种方式形成的单词。 

示例 1:

输入:"{a,b}c{d,e}f"
输出:["acdf","acef","bcdf","bcef"]

示例 2:

输入:"abcd"
输出:["abcd"] 

提示:

  1. 1 <= S.length <= 50
  2. 你可以假设题目中不存在嵌套的花括号
  3. 在一对连续的花括号(开花括号与闭花括号)之间的所有字母都不会相同

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转载自www.cnblogs.com/strengthen/p/11031602.html