前二十个偶数和奇数的和

#include <iostream>
using namespace std;
int main() 
{
	int s1=0,i,j,s2=0,n;
	for(i=1,j=2,n=0;n<20;n++,i=i+2,j=j+2)
	{
		s1=s1+i;
		s2=s2+j;
	}
	cout<<s1<<" "<<s2;
	return 0;
}

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转载自blog.csdn.net/weixin_43822669/article/details/90548543