通过元类简单实现ORM中的insert功能

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class ModelMetaclass(type):
    def __new__(cls, name, bases, attrs):
        mappings = dict()
        # 判断是否需要保存
        for k, v in attrs.items():
            # 判断是否是指定的StringField或者IntegerField的实例对象
            if isinstance(v, tuple):
                print('Found mapping: %s ==> %s' % (k, v))
                mappings[k] = v

        # 删除这些已经在字典中存储的属性
        for k in mappings.keys():
            attrs.pop(k)

        # 将之前的uid/name/email/password以及对应的对象引用、类名字
        attrs['__mappings__'] = mappings  # 保存属性和列的映射关系
        attrs['__table__'] = name  # 假设表名和类名一致
        return type.__new__(cls, name, bases, attrs)


class User(metaclass=ModelMetaclass):
    uid = ('uid', "int unsigned")
    name = ('username', "varchar(30)")
    email = ('email', "varchar(30)")
    password = ('password', "varchar(30)")
    # 当指定元类之后，以上的类属性将不在类中，而是在__mappings__属性指定的字典中存储
    # 以上User类中有 
    # __mappings__ = {
    #     "uid": ('uid', "int unsigned")
    #     "name": ('username', "varchar(30)")
    #     "email": ('email', "varchar(30)")
    #     "password": ('password', "varchar(30)")
    # }
    # __table__ = "User"
    def __init__(self, **kwargs):
        for name, value in kwargs.items():
            setattr(self, name, value)

    def save(self):
        fields = []
        args = []
        for k, v in self.__mappings__.items():
            fields.append(v[0])
            args.append(getattr(self, k, None))

        sql = 'insert into %s (%s) values (%s)' % (self.__table__, ','.join(fields), ','.join([str(i) for i in args]))
        print('SQL: %s' % sql)


u = User(uid=12345, name='Michael', email='[email protected]', password='my-pwd')
# print(u.__dict__)
u.save()

执行的效果:

Found mapping: password ==> ('password', 'varchar(30)')
Found mapping: email ==> ('email', 'varchar(30)')
Found mapping: uid ==> ('uid', 'int unsigned')
Found mapping: name ==> ('username', 'varchar(30)')
SQL: insert into User (uid,password,username,email) values (12345,my-pwd,Michael,[email protected])