SQL - 读取XML中的节点

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-- 取得节点的值
select q.XmlContent.value('(//Root/Items/Item/_Name)[1]','nvarchar(max)') AS ColumnName  FROM [dbo].[TableName] q
-- 取得节点
select q.XmlContent.query('(//Root/Items/Item/_Name)') AS ColumnName FROM [dbo].[TableName] q