2019-06-12：今日头条测试开发面试编程题：123456789隔三个字符反转成321654987

def dellWithNums(s):
    saveNums=[]

    for i in [0,3,6]:
        saveNums.append(s[i:i+3])
    print(saveNums)
    tarNums=[]
    for j in saveNums:
        #print(j)
        tarChar=j[::-1]
        tarNums.append(tarChar)
    return "".join(tarNums)
s='123456789'
print(dellWithNums(s))