Codeforces 954A - Diagonal Walking（简单数学）

Problem Description

Mikhail walks on a 2D plane. He can go either up or right. You are given a sequence of Mikhail's moves. He thinks that this sequence is too long and he wants to make it as short as possible.

In the given sequence moving up is described by character U and moving right is described by character R. Mikhail can replace any pair of consecutive moves RU or UR with a diagonal move (described as character D). After that, he can go on and do some other replacements, until there is no pair of consecutive moves RU or UR left.

Your problem is to print the minimum possible length of the sequence of moves after the replacements.

Input   

The first line of the input contains one integer n (1 ≤ n ≤ 100) — the length of the sequence. The second line contains the sequence consisting of n characters U and R.

Output  

Print the minimum possible length of the sequence of moves after all replacements are done.

Examples 

Input

5 RUURU

Output

3

Input

17 UUURRRRRUUURURUUU

Output

13

Note 

In the first test the shortened sequence of moves may be DUD (its length is 3).

In the second test the shortened sequence of moves can be UUDRRRDUDDUUU (its length is 13).

题意：

R，U， RU， UR都算一步，如果RR，UU就是两步,问题目所给的字符串可以缩短为的最短步数。

 

代码：

#include<bits/stdc++.h>
using namespace std;
int main(){
	int n;
        char a[110]; 
	cin>>n;
        cin>>a;
	int num=0;
	for(int i=0;i<n-1;i++){
		if(a[i]!=a[i+1]){
			num++;
			i++;
		}
	}
	cout<<n-num;
	return 0;
}