第四次作业——潘芊睿

设计题1:

设计一个本月份日历,输出格式如下:
7fe1d8a9ea403301e3d8e953b3b2748.png

要求:
1.初始化start_day,end_day两个日期
from datetime import datetime
start_day=datetime(2019,4,1)
end_day=datetime(2019,4,30)
其它时间数据生成要用datetime或date模块的方法编程实现
2.不能使用calendar模块生成

from datetime import datetime
from datetime import timedelta
from datetime import *
start_day = datetime(2019, 4, 1)
end_day = datetime(2019, 4, 30)
a=end_day-start_day
amount = a.days + 1
first=start_day.isoweekday()
k = 1
count=0
print("\t\t\t2019年4月")
print("星期一 星期二 星期三 星期四 星期五 星期六 星期日")
while k < first:
    k=k+1
    print("\t", end="   ")
p = 1
while p <= amount:
    print(p, "\t", end="   ")
    p =p+1
    count =count+1
    if (count % 7 == 0):
        print("\n")

 

设计题2:

1.参考“三国演义”词频统计程序,实现对红楼梦出场人物的频次统计。
2.(可选)
将红楼梦出场人物的频次统计结果用词云显示。

import jieba

excludes = {"什么", "一个", "我们", "那里", "你们", "如今", "说道", "知道", "起来", "姑娘", "这里", "出来", "他们", "众人", "自己",
            "一面", "只见", "太太", "奶奶", "两个", "没有", "不是", "不知", "这个", "听见", "这样", "进来", "咱们", "告诉", "怎么",
            "就是", "东西", "回来", "只是", "老爷", "大家", "只得", "丫头", "这些", "不敢", "出去", "所以", "的话", "不好", "姐姐",
            "鸳鸯"}
txt = open("红楼梦.txt", "r", encoding='utf-8').read()
words = jieba.lcut(txt)
counts = {}
for word in words:
    if len(word) == 1:
        continue
    elif word == "宝玉" or word == "宝二爷" or word == "怡红公子" or word == "绛洞花主" or word == "无事忙" or word == "遮天大王" or word == "混世魔王" or word == "槛内人" or word == "浊玉":
        rword = "贾宝玉"
    elif word == "颦颦" or word == "颦儿" or word == "潇湘妃子" or word == "林姑娘" or word == "林妹妹" or word == "黛玉":
        rword = "林黛玉"
    elif word == "凤姐" or word == "琏二奶奶" or word == "凤辣子" or word == "凤哥儿" or word == "凤丫头" or word == "凤姐儿":
        rword = "王熙凤"
    elif word == "贾母" or word == "老太太":
        rword = "贾母"
    elif word == "宝钗" or word == "蘅芜君" or word == "宝姐姐" or word == "宝丫头" or word == "宝姑娘":
        rword = "薛宝钗"
    else:
        rword = word
    counts[rword] = counts.get(rword, 0) + 1
for word in excludes:
    del (counts[word])
items = list(counts.items())

items.sort(key=lambda x: x[1], reverse=True)

for i in range(10):
    word, count = items[i]
    print("{0:<10}{1:>5}".format(word, count))

 

猜你喜欢

转载自www.cnblogs.com/pangaogao/p/10835241.html