C# 字符串转JSON

 一、简单小结

C# 中 String 转 JSON

var items = JsonConvert.DeserializeObject<class>(stringJSON);

这里的 class 最好是直接定义 dto 来接收,不然不好变量和取值。

二、使用案例

  json 字符串:

[{"name":"温度A","id":"W1","measure":"°C","precision":0,"max":10,"min":0,"expression":"","map":"d1","value":"最大值"},{"name":"温度B","id":"W2","measure":"°C","precision":0,"expression":"","map":"d2","value":"最大值"},{"name":"拉力计A","id":"L1","measure":"Pa","precision":0,"expression":"","map":"d3","value":"最大值"}]

  类:StatTemplateStateDto

public class StatTemplateStateDto
    {
        /// <summary>
        /// 映射标识
        /// </summary>
        public virtual String Id { get; set; }

        /// <summary>
        /// 名称
        /// </summary>
        public virtual String Name { get; set; }

        /// <summary>
        /// 单位
        /// </summary>
        public virtual String Measure { get; set; }

        /// <summary>
        /// 最小值
        /// </summary>
        public virtual String Precision { get; set; }

        /// <summary>
        /// 公式
        /// </summary>
        public virtual String Expression { get; set; }

        /// <summary>
        /// 映射
        /// </summary>
        public virtual String Map { get; set; }

        /// <summary>
        /// 特征值
        /// </summary>
        public virtual String Value { get; set; }

    }

 转换代码:

var items = JsonConvert.DeserializeObject<StatTemplateStateDto[]>(input.StatTemplate.Content);

猜你喜欢

转载自www.cnblogs.com/gzbit-zxx/p/10831906.html
今日推荐