D. Masquerade strikes back(思维)

https://codeforces.com/gym/101911/problem/D

题解: set打表存因子会炸  数据大到1e7,开不了

            所以看代码:得先找到重复的几个数直接挨个分配一组因子

#include<cstdio>
#include<cstring>
#include<string.h>
#include<algorithm>
#include<iostream>
#include<stdlib.h>
using namespace std;
const int inf=0x3f3f3f3f;
const int maxn=1000000;
struct node{
	int x;
	int y;
	int z;
	int id;
}s[maxn];
bool cmp1(node a,node b){
	return a.x<b.x;
}
bool cmp(node a,node b){
	return a.id<b.id;
}
int  main(){
	int n;
	cin>>n;
	for(int i=0;i<n;i++){
		cin>>s[i].x;
		s[i].id=i;
	}
	sort(s,s+n,cmp1);
	int flag=0;
	for(int i=0;i<n;i++){
		int r=i;
		int l=i;
		int k=s[i].x;
		while(s[i].x==s[r+1].x){
			r++;
		}
		i=r;
	//	cout<<l<<' '<<r<<endl;
		for(int j=1;j*j<=k;j++){
			if(k%j==0){
				s[l].y=j;
				s[l].z=k/j;	
			l++;
			if(l>r) break;
			if(j==k/j)  break;
			s[l].y=k/j;
			s[l].z=j;
			l++;//成对的话就是两因子交换 
			if(l>r) break;
		    }
		}
	//	cout<<l<<" 1 "<<r<<endl;
		if(l<=r){
			flag=1;
			break;
		}
	}
	if(flag){
		cout<<"NO"<<endl;
	}else{
		cout<<"YES"<<endl;
		sort(s,s+n,cmp);
		for(int i=0;i<n;i++){
			cout<<s[i].y<<" "<<s[i].z<<endl;
		}
	}
}

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转载自blog.csdn.net/gml1999/article/details/89742768