【C语言】在整形有序数组中查找想要的数，找到输出下标

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main()
{
	int a[10];
	int i;
	printf("请输入一个长度为10的整形数组：\n");
	for (i = 0; i < 10; i++)
	{
		scanf("%d", &a[i]);
	}
	int left=0;
	int sz = sizeof(a) / sizeof(a[0]);//数组元素个数
	int right = sz - 1;
	int tmp;
	printf("输入要找的数:\n");
	scanf("%d", &tmp);
	while (left <= right)
	{
		int mid = left + (right - left) / 2;
		if (a[mid] == tmp){
			printf("找到了，下标为%d", mid);
			break;
		}
		else if (a[mid] <= tmp){
			left = mid + 1;
		}
		else{ right = mid - 1; }
	}
	if (left > right){
		printf("找不到！");
	}
	system("pause");
	return 0;
}