C# 指定程序打开指定文件

            Process process = new Process();
            process.StartInfo.FileName = 指定程序exe文件路径;
            process.StartInfo.Arguments = 指定文件路径;
            process.StartInfo.UseShellExecute = false; 
            process.StartInfo.RedirectStandardOutput = false;
            process.StartInfo.RedirectStandardInput = true;
            process.StartInfo.CreateNoWindow = false;
            process.Start();
            process.WaitForExit();
            process.Close();

猜你喜欢

转载自www.cnblogs.com/alinawang/p/10790870.html