链表基础面试题(部分)

//三个指针反转单链表
struct ListNode *reverserList(struct ListNode *head)
{
   struct ListNode *p1 = NULL;
   struct ListNode *p2 = head;
   struct ListNode *p3 = head->next;
   while (p2 != NULL)
   {
     p2->next =p1;
      p1 = p2;
      p2 = p3;
      if (p3 != NULL)
      {
         p3 =p3->next;
      }
   }
}
 
//链表的中间结点(双指针倍速遍历,要是双数个链表停在中间的后面结点)
struct ListNode *middleNode(struct ListNode *head)
{
   struct ListNode *fast =head;
   struct ListNode *slow =head;
   while (fast!= NULL)
   {
      fast =fast->next;
      if (fast!= NULL)
         break;
      slow =slow->next;
      fast =fast->next;
   }
   return  slow;
}
 
//求倒数第k个结点往后
struct ListNode *FindKthToTail(struct ListNode *pListHead, int k)
{
   int i;
   struct ListNode *front= pListHead;
   struct ListNode *back =pListHead;
   for ( i =0; front != NULL && i < k; i++)
   {
      front =front->next;
   }
  if (i <k)
   {
      return NULL;
   }
   while (front)
   {
      front =front->next;
      back =back->next;
   }
   return back;
}

 


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