python斐波那切数列1,1,2,3,5,8,13,21,…,编程求第n个斐波那契数列的数

def fbql(x):
    if x == 1 or x ==2:
        return 1
    else:
        return fbql(x-1)+fbql(x-2)

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转载自www.cnblogs.com/beiyue/p/10766605.html