MySql按周,按月,按日分组统计数据、日期计算。并统计环比、同比

MySql按周,按月,按日分组统计数据

<!-- 按日查询 -->  
SELECT DATE_FORMAT(created_date,'%Y-%m-%d') as time,sum(money) money FROM o_finance_detail where org_id = 1000  GROUP BY  time  
<!-- 按月查询 -->  
SELECT DATE_FORMAT(created_date,'%Y-%m') as time,sum(money)  money FROM o_finance_detail where org_id = 1000  GROUP BY  time  
<!-- 按年查询 -->  
SELECT DATE_FORMAT(created_date,'%Y') as time,sum(money)  money FROM o_finance_detail where org_id = 1000  GROUP BY  time   
<!-- 按周查询 -->  
SELECT DATE_FORMAT(created_date,'%Y-%u') as time,sum(money)  money FROM o_finance_detail where org_id = 1000  GROUP BY  time  

以下使用的字符串time为自定义名字的字段
-- 今天
select*from time_test where to_days(time)=to_days(now());
-- 昨天
select*from time_test where datediff(time,now())=-1;
-- 本周
select * from time_test where yearweek(date_format(time,'%Y-%m-%d'))=yearweek(now());
-- 上周
select * from time_test where yearweek(date_format(time,'%Y-%m-%d'))=yearweek(now())-1;
-- 本月
select * from time_test where date_format(time,'%Y%m')=date_format(curtime(),'%Y%m') order by time;
-- 上个月
select * from time_test where 
period_diff(
	date_format(now(),'%Y%m') , date_format(time,'%Y%m') 
	)=1 order by time
-- 近7天
select * from time_test where date_sub(curdate(),interval 7 day) <=date(time) order by time
-- 近30天
select * from time_test where date_sub(curtime(),interval 30 day) <= date(time) order by time
-- 本季度
select * from time_test where quarter(time)=quarter(now()) order by time
-- 上季度
select * from time_test where quarter(time)=quarter( 
date_sub( now(),interval 1 quarter ) 
)
-- 本年
select * from time_test where year(time)=year(now()) order by time;
-- 去年
select * from time_test where year(time)=year(date_sub(now(),interval 1 year)) order by time;
DATE_FORMAT(date,format) 
根据format字符串格式化date值。下列修饰符可以被用在format字符串中: 
%M 月名字(January……December) 
%W 星期名字(Sunday……Saturday) 
%D 有英语前缀的月份的日期(1st, 2nd, 3rd, 等等。) 
%Y 年, 数字, 4 位 
%y 年, 数字, 2 位 
%a 缩写的星期名字(Sun……Sat) 
%d 月份中的天数, 数字(00……31) 
%e 月份中的天数, 数字(0……31) 
%m 月, 数字(01……12) 
%c 月, 数字(1……12) 
%b 缩写的月份名字(Jan……Dec) 
%j 一年中的天数(001……366) 
%H 小时(00……23) 
%k 小时(0……23) 
%h 小时(01……12) 
%I 小时(01……12) 
%l 小时(1……12) 
%i 分钟, 数字(00……59) 
%r 时间,12 小时(hh:mm:ss [AP]M) 
%T 时间,24 小时(hh:mm:ss) 
%S 秒(00……59) 
%s 秒(00……59) 
%p AM或PM 
%w 一个星期中的天数(0=Sunday ……6=Saturday ) 
%U 星期(0……52), 这里星期天是星期的第一天 
%u 星期(0……52), 这里星期一是星期的第一天 
%% 一个文字“%”。

统计环比、同比

用已有的案例解释,参考https://blog.csdn.net/pengyangchao/article/details/85990711

有一个业务需求 ,统计各个景区的入园人数、销售额以及入园人数和销售额的同比,以月度为例子同比为例;环比类似

思路分析:表a首先统计出当月的入园人数、销售额,表b统计出同期的入园人数、销售额(在a的基础上减去一年,可),将两个表进行左连接


select 
    CASE WHEN b.TOTAL_COUNT is NULL OR b.TOTAL_COUNT=0 THEN 0 
    ELSE ((a.TOTAL_COUNT - b.TOTAL_COUNT)/b.TOTAL_COUNT)*100 //计算入园人数同比 
    END link_ratio_count, 
    CASE WHEN b.total_money is NULL OR b.total_money=0 THEN 0 
    ELSE ((a.total_money - b.total_money)/b.total_money)*100 //计算销售额同比
    END link_ratio_money,
a.TOTAL_COUNT as total_count_this,b.TOTAL_COUNT as total_count_last,a.total_money as total_money_this,b.total_money as total_money_last,a.PROJECT_NAME,a.PROJECT_NO 
FROM 
    (SELECT SUM(TOTAL_COUNT) as TOTAL_COUNT,SUM(PAY_MONEY-RETURN_COUNT*o.SELLER_PRICE) as total_money,PROJECT_NAME,o.PROJECT_NO 
	    FROM S_ORDER_C o 
	    LEFT JOIN S_PRODUCT d ON o.PRODUCT_NO=d.PRODUCT_NO 
        where DateDiff(mm,o.CREATE_TIME,GETDATE()) <= 1// sql server的写法筛选近一月
	    GROUP BY PROJECT_NAME,o.PROJECT_NO) a //根据景区名称和景区编码分组 
LEFT JOIN 
    (SELECT SUM(TOTAL_COUNT) as TOTAL_COUNT,SUM(PAY_MONEY-RETURN_COUNT*o.SELLER_PRICE) as total_money,PROJECT_NAME 
        FROM S_ORDER_C o 
	    LEFT JOIN S_PRODUCT d ON o.PRODUCT_NO=d.PRODUCT_NO 
	    where  DateDiff(mm,o.CREATE_TIME,'2018-01-01') = 0 
	    GROUP BY PROJECT_NAME) b ON a.PROJECT_NAME = b.PROJECT_NAME

日期计算

1. MySQL 为日期增加一个时间间隔:date_add()

set @dt = now();

select date_add(@dt, interval 1 day);        -- add 1 day
select date_add(@dt, interval 1 hour);       -- add 1 hour
select date_add(@dt, interval 1 minute);     -- ...
select date_add(@dt, interval 1 second);
select date_add(@dt, interval 1 microsecond);
select date_add(@dt, interval 1 week);
select date_add(@dt, interval 1 month);
select date_add(@dt, interval 1 quarter);
select date_add(@dt, interval 1 year);

select date_add(@dt, interval -1 day);       -- sub 1 day

MySQL adddate(), addtime()函数,可以用 date_add() 来替代。下面是 date_add() 实现 addtime() 功能示例:

2. MySQL 为日期减去一个时间间隔:date_sub()

mysql> select date_sub('1998-01-01 00:00:00', interval '1 1:1:1' day_second);

+----------------------------------------------------------------+
| date_sub('1998-01-01 00:00:00', interval '1 1:1:1' day_second) |
+----------------------------------------------------------------+
| 1997-12-30 22:58:59                                            |
+----------------------------------------------------------------+

MySQL date_sub() 日期时间函数 和 date_add() 用法一致,不再赘述。另外,MySQL 中还有两个函数 subdate(), subtime(),建议,用 date_sub() 来替代。

4. MySQL 日期、时间相减函数:datediff(date1,date2), timediff(time1,time2)

MySQL datediff(date1,date2):两个日期相减 date1 - date2,返回天数。

select datediff('2008-08-08', '2008-08-01');  -- 7
select datediff('2008-08-01', '2008-08-08');  -- -7

MySQL timediff(time1,time2):两个日期相减 time1 - time2,返回 time 差值。

select timediff('2008-08-08 08:08:08', '2008-08-08 00:00:00'); -- 08:08:08
select timediff('08:08:08', '00:00:00');                       -- 08:08:08

注意:timediff(time1,time2) 函数的两个参数类型必须相同。

实操:

SELECT
	NAME AS 名称,
	date_format(
		from_unixtime(create_time),
		'%Y-%m-%d'
	) AS 创建时间,
	date_format(
		from_unixtime(last_login_time),
		'%Y-%m-%d'
	) AS 上次登录时间,
	login_count AS 登录次数,
	cast(
		login_count / (
			datediff(
				date_format(
					from_unixtime(last_login_time),
					'%Y-%m-%d'
				),
				date_format(
					from_unixtime(create_time),
					'%Y-%m-%d'
				)
			)
		) AS DECIMAL (10, 2)
	) AS `登录频率(次/天)`
FROM
	peoplebank_farmer
ORDER BY
	login_count DESC

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转载自blog.csdn.net/weixin_40096730/article/details/89177736