MySQL求每个用户当月是否消费过

SELECT userId,DATE_FORMAT(paidTime,"%Y%m-01")
from learn.order_info_utf
GROUP BY userId,DATE_FORMAT(paidTime,"%Y%m-01")
  • 使用left join
SELECT t1.m,count(t1.m),count(t2.m) FROM (
	SELECT userId,DATE_FORMAT(paidTime,"%Y-%m-01") as m
	from learn.order_info_utf
	WHERE Ispaid = "已支付"
	GROUP BY userId,DATE_FORMAT(paidTime,"%Y-%m-01")) t1
left JOIN (
	SELECT userId,DATE_FORMAT(paidTime,"%Y-%m-01") as m
	from learn.order_info_utf
	WHERE Ispaid = "已支付"
	GROUP BY userId,DATE_FORMAT(paidTime,"%Y-%m-01")) t2
ON  t1.userId = t2.userId and t1.m = DATE_SUB(t2.m,INTERVAL -1 MONTH)
GROUP BY t1.m

*注意【%Y-%m-01】之间的【-】

  • 最好创建view,更有效率
create algorithm = undefined view tmp
as  
SELECT userId,DATE_FORMAT(paidTime,"%Y%m-01")
from learn.order_info_utf
GROUP BY userId,DATE_FORMAT(paidTime,"%Y%m-01")
SELECT t1.m,count(t1.m),count(t2.m) FROM tmp as t1
left JOIN tmp as  t2
ON  t1.userId = t2.userId and t1.m = DATE_SUB(t2.m,INTERVAL -1 MONTH)
GROUP BY t1.m

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转载自blog.csdn.net/DataFrame/article/details/84674889